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In the last exercise, you have shown how an XOR gate can act as an inverter. In this exercise, show that a 2-input XOR gate can act as a buffer that simply passes input to the output. Now explain why the XOR gate is called a programmable inverter.


In our discussion of the 3-input majority function, we have assigned equal weight (i.e., 1/3) to the three inputs. Suppose that one input has a weight of 1/2 and the other two inputs have 1/4 each. Show the truth table for the weighted 3-input majority function. Derive a simplified logical expression and show the corresponding implementation.




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